If it's not what You are looking for type in the equation solver your own equation and let us solve it.
=-3Y^2-30Y+7
We move all terms to the left:
-(-3Y^2-30Y+7)=0
We get rid of parentheses
3Y^2+30Y-7=0
a = 3; b = 30; c = -7;
Δ = b2-4ac
Δ = 302-4·3·(-7)
Δ = 984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{984}=\sqrt{4*246}=\sqrt{4}*\sqrt{246}=2\sqrt{246}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{246}}{2*3}=\frac{-30-2\sqrt{246}}{6} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{246}}{2*3}=\frac{-30+2\sqrt{246}}{6} $
| 9x+5-4x=15 | | 6t+10=-6-5t-9t | | 2(r-2.7)=6.4 | | w−812=3 | | 9h+9(5h+5)=3+2h-10 | | 9h+9(5h+5)=2h-10 | | -1x+11=-24+1x | | -r+6=-2r-4 | | f7+10=20 | | +1x+11=-24+1x | | 12=2x-6-4x-4 | | 10+z=-3(-2z+10) | | 10+z=-3(-2+10) | | 100=4(1+3x) | | -7(-7m-10)=-10+9m | | 4(-6y-3)=2+5(-6y-10) | | 40h+9h+7h−53h=18 | | 5m+200=535 | | F(-3)=2(x)^2x+9 | | 2(4×+1)-3=8x+1 | | (x-2)^2+8=-17 | | 1/3y+5=-10 | | 11-4g=-6.56 | | 2k−2=–4k−8 | | –10−10d=–5+10 | | x+79=115 | | 0.5(6x-2)=4x-9 | | –10−10d=–5d+10 | | 24=k×4 | | -4b-9+3=-2b+10 | | 3n=3.3=86.7 | | (15x-2)(7x+4)=x |